If a diver's surface air consumption rate is 25 psi per minute, what would be the consumption rate at 66 feet of seawater?

To determine the consumption rate at 66 feet of seawater, it's essential to consider the effects of pressure on air consumption while diving. As a diver descends, the pressure increases, which means that the amount of air in the tank becomes denser.

At sea level, the pressure is 1 atmosphere (atm), which is equivalent to approximately 14.7 psi. Every 33 feet of seawater adds about 1 atm of pressure. Thus, at 66 feet, the pressure would be about 3 atm (1 atm for surface pressure + 2 atm for the two additional increments of 33 feet). This total results in a pressure of approximately 3 times 14.7 psi, which equals about 44.1 psi.

Since the surface air consumption rate is 25 psi per minute at 1 atm, when the pressure increases to 3 atm, the diver experiences a higher rate of consumption due to increased density of air. The surface air consumption rate adjusts proportionally to the pressure changes.

To calculate the adjusted consumption rate:

Divide the surface air consumption rate by the number of atm at that depth.

In this case, you would take 25 psi and divide it by 3 (since it